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burgess87
Jun 30, 2014, 10:53 PM
What is the least number, which when divided by 48,60,72,108 and 140 leaves remainders 38,50,62,98 and 130 respectively?

Please tell me the answer and procedure to solve this problem

ma0641
Jul 1, 2014, 07:08 AM
We don't tell you answers here. Show us your work and we can help.

ebaines
Jul 1, 2014, 01:59 PM
Here's a hint to get you started. Suppose the answer is 'A' - note that dividing A by each of these divisors leaves a remainder that is 10 less than the divisor. Therefore all of these divisors divide into A +10 without a remainder. Hence A+10 is the least common multiple of 48, 60, 72, 108 and 140. Can you complete it now?