A ball is thrown horizontally at 20 m/s from a bridge that is 42 m high. Calculate the speed at which the ball strikes the water below

Hint: break it down into horizontal and vertical components of motion.

So x comp is the 20m/s and y comp is gravity and height ?

So x comp is the 20m/s and y comp is gravity and height ?

Yes

Use one of your kinetic formulas, they're three basic ones.

I'm really confused. Could you please show me, with working? Please! :) I'm super desperate haha

First determine the vertical component of velocity of the projetile when it hits the gropund, after falling with acceleration 'g' for a distance of 42 m. This formula ought tio look familiar"

v_f^2 - v_i^2 = 2ad

Here v_i =0,\ a = -g, \ d=42\m, now solve for v_f. The horizontal component of velocity you already know. Finally use Pythagoras to find the magnitude of the velocity at impact.