a .500kg sample of water is at 15 degrees C in a calorimeter. A .0400kg mass of zinc at 115 degrees C is placed in the water. What is the final temp of the system if specific heat of zinc is 388J/kg/C and the specific heat of water is 4184J/kg/C?

This was the exact question goven to me I think it has something to do with the formula Q=mcDeltaT and energy has to always be at a constant since it can't be either destroyed or created, BUT don't take my word on that.

ANY help wrong or hopefully otherwise would be greatly appreciated.

Well, the water has to gain the same energy as the zinc loses, and the system has to come to an equal temperature.

Using these 2 pieces of information, you should be able to form equations and solve them.

a .500kg sample of water is at 15 degrees C in a calorimeter. a .0400kg mass of zinc at 115 degrees C is placed in the water. what is the final temp of the system if specific heat of zinc is 388J/kg/C and the specific heat of water is 4184J/kg/C?

This was the exact question goven to me i think it has something to do with the formula Q=mcDeltaT and energy has to always be at a constant since it can't be either destroyed or created, BUT dont take my word on that.

ANY help wrong or hopefully otherwise would be greatly appreciated.
m1*s1*[T-(273+15)] = m2*s2*[273+115-T]

(m1*s1+m2*s2)T = m2*s2*388 +m1*s1*288

T= {(.04*388*388)+(.5*4184*288)}/(.04*388 +.5*288)

= X kelvin

=X-273 deg c