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coolfield7
Nov 19, 2013, 10:51 AM
Hi, I have a question relating to percentages. I have this situation in my town and I was just wondering... a store near me sells a block of butter for $2.00, another store sells the same butter for $5.00. The second store is selling it for $3.00 more... how would I find the difference in a percentage?

Thanks?

ebaines
Nov 19, 2013, 10:55 AM
Percentage difference is expressed as the difference between second and first values divided by the first value, times 100%. Thus a $5 stick of butter is (5-2)/2 x 100% = 150% higher price than the $2 stick of butter.

coolfield7
Nov 19, 2013, 05:15 PM
Percentage difference is expressed as the difference between second and first values divided by the first value, times 100%. Thus a $5 stick of butter is (5-2)/2 x 100% = 150% higher price than the $2 stick of butter.
Exactly what I was looking for. Thanks!

coolfield7
Nov 19, 2013, 10:48 PM
Percentage difference is expressed as the difference between second and first values divided by the first value, times 100%. Thus a $5 stick of butter is (5-2)/2 x 100% = 150% higher price than the $2 stick of butter.
I have one other question that I'm stumped over. In my textbook it says, " 3 persons, A, B, and C enter a business together; they contribute $50,000, $60,000, and $100,000 respectively. In a particular year the profit they make is $224,000. The profit is shared among A, B, and C in proportion to their contributions."
I'm having trouble finding each of their profit, I tried a lot but my answers are always off from the answers from the book.

Thanks again. You've helped me A LOT