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Amir2020
Nov 17, 2013, 04:00 PM
A stationary elevator and its contents have a combined mass of 2000kg. The elevator is suspended by a single cable. If the elevator is decending at 4.0m/s squared, what are the values of all the forces acting at this point?
ma0641
Nov 17, 2013, 05:15 PM
You posted this twice. Someone, if they want.to, will get to you. Remember, we don't do YOUR homework.
ebaines
Nov 18, 2013, 09:18 AM
Remember that \sum \vec F = m \vec a. Here the forces acting in the elevator are the tension in the cable (which is positive value because it operates in the positive y direction) and the force of gravity in the negative y direction. You have a value for \vec a (be careful to use the correct sign), now solve for \vec T.