hamda51
Nov 10, 2013, 12:45 PM
My question is to make the right side equal the left side
ebaines
Nov 11, 2013, 06:38 AM
What you wrote is incorrect. You wrote this:
\frac {\tan x}{sec x} -1 = secx + \frac 1 {tanx}
You must learn to use parentheses to avoid mistakes like that. I suspect what you really meant is this:
tanx/(secx -1) = (secx + 1)/tanx
Hint: start by cross-multiplying the fractions on the left and right hand sides, then replace the secx and tanx functions with their sine and cosine equivalents.