I need help! I am also new to this...

question:

find the zeros of f(X)=(4x^2-49) / (2x+7)

This isn't bad.

The numerator is the difference of two squares. x^{2}-y^{2}=(x-y)(x+y)

You have:
.\text{x}.......\text{y}
.{\downarrow}.......{\downarrow}
\frac{(2x)^{2}-(7)^{2}}{2x+7}

Continue? It'll simplify down to something very easy.