solve the following equation in the given interval : sec
ebaines
Jan 22, 2013, 08:02 AM
Hint: start by converting the sec(2x) to 1/cos(2x), and the cos(90-2x) to sin(2x). Then I suggest put the sin(2x) term into sqrt(1-cos^2(2x)), rearrange and solve for cos(2x).