this question is of vector concept-
a car travelling at 36km/h north turns west in 5 seconds and maintains the same speed.what is the magnitude and direction of acceleration of the car?
Answer is 2√2 m/s^2 along south west direction .Here I have a problem that how it can be along south west direction as south direction is not even in question.please help

The acceleration can be calculated from


\vec a = \frac {\Delta \vec v} {t} = \frac {\vec v_2 - \vec v_1} t


Note that velocity is a vector, so you need to find the difference between a vector of magnitude 10 m/s north minus 10 m/s west, and divide by 5 seconds.