You throw a ball straight into the air from a height of 4 feet and with a speed of 6.96 m/s. The moment the ball leaves your hand you start running away at a speed of 2.37 m/s. How far are you from the ball, the moment it hits the ground?

First step is to determine the time the ball is in the air. Do you know how to use the equation:


x(t) = x_0 + v_0t + \frac 1 2 a t^2


to find 't'?