Compute P(E|F) AND P(F|E) GIVEN P(E)=.4 P(F)=.6 AND P(E AND F)= .23

And you tried what exactly?

Compute P(E|F) AND P(F|E) GIVEN P(E)=.4 P(F)=.6 AND P(E AND F)= .23

As I said before...

And you tried what exactly?

I have the formula E|F=p(E AND F)/pF but I don't get how to work it.

You have:

P(E|F) = \frac{P(E\ \cap\ F)}{P(F)}

What is P(E\ \cap\ F)?

What is P(F)?

so it P(E|F)= .23/.6 AND P(F|E)= .23/.40?

You nailed it :)

It wasn't that hard, right?

Thank you...