hashsansen
Jul 8, 2012, 10:50 PM
16^sin(20)^sin(40)^sin(60)^sin(80)=3
ebaines
Jul 9, 2012, 11:38 AM
16^sin(20)^sin(40)^sin(60)^sin(80)=3
No it doesn't:
((((16^{\sin (20)})^{\sin (40)}) ^ {\sin (60)})^ {\sin (80)} = 16^{\sin(20) \times \sin(40) \times \sin(60) \times \sin(80)} \ne 3