f(x)= x+2/x+6

Although what az130 says is right, he has missed the negative values that f(x) is positive for too, these are the values below -6.

I have plotted a graph, the blue line is your function, you ca see it is positive above -2 and below -6

at x=-6 I have drawn the asymptote, this is a line that the equation approached but never touches.

Hope this helps.

Capuchin, can we come up with how to solve this without a graph?

I can do it like this but I'm not happy with it. The second portion seems mathematically correct but obviously leads to the wrong answer. The 0 is causing problems. How do we use algebra to get both answers? How would you find the roots if it were = instead of >? Oh well, it's early for me so maybe my brain will come up to speed later :)


\frac {x+2} {x+6} > 0 \\
x+2 > 0 * \left(x+6\right) \\
x > -2


and


\frac {x+2} {x+6} > 0 \\
\frac {\left(x+6\right)^2} {\left(x+2\right)^2} \frac {x+2} {x+6} > 0 \\
\frac {x+6} {x+2} > 0 \\
x+6 > 0 * \left(x+2\right) \\
x > -6


edit: i think the key is that we can't normally multiply both sides by something with an x without causing troubles and like i said, the 0 isn't helping.

Oh yes, I did it in my head without a graph, I just find it easier to show it that way.

Thank you for putting it more clearly than az130

:)