OK so the equation is balanced and is:
3Mg + 2AlCl(3) ---> 3MgCl(2) + 2Al
I am given:
mass of crucible and Mg: 34.61g
mass of crucible alone: 28.43g
mass of crucible and Al: 32.42g

I was told to subtract the crucible weight from the other 2 measurements so Mg = 6.18g and Al = 3.99g

I just really need help with answering the questions and if you can tell me how you did it that would be great! The questions are:
1) What mass of Mg is used in the reaction?
2) What is the mass of Al produced?
3) What is the Theoretical Yield of AL?
4) What is the percent yield of the reaction?