I have 2 put this in descending powers...
7x-2+3xto the 5th power - 4x to the 2nd power +x to the 4th power
is the answer..
7x-2 +x to the 4th power
3xto the 5th power - 4x to the 2nd power +x to the 4th power +7x-2
is this correct?

I have 2 put this in descending powers...
7x-2+3xto the 5th power - 4x to the 2nd power +x to the 4th power
is the answer..
7x-2 +x to the 4th power
3xto the 5th power - 4x to the 2nd power +x to the 4th power +7x-2
is this correct?

Please do not double-post questions. Are you in middle school or high school?

Middel school but going in2 high school so I wasn't sure of which one I shld write! But are you gonnna help me w/ my problom?
Thanks if you are !

Please help me I have a MATH FINAL!!

So your answer is:


3x^5-4x^2 +x^4+ 7x -2


Remember that x = x^1, and a constant like -2 is equivalent to -2x^0
and would it change you answer?

awsome thanks but what about if I have 2 put in assending powers on...
x to the third power -3 -5x + x to the second power?

awsome thnx but wat about if i have 2 put in assending powers on...
x to the third power -3 -5x + x to the second power??

Qwerty - first it's helpful to use the carat character "^" as shorthand for "to the power of." Hence you are asking about this:

x^3-3-5x+x^2

Same process as before: replace the -3 by -3x^0 and -5x by -5x^1, and you get:

x^3 -3x^0-5x^1+x^2

Can you put this in order of ascending powers of x?

so it would be..
(ascending is from smallest 2 freatest right?)
x^2+x^3-3x^0-5x^1


but why did u put -5x^1 have a 1 why not a zero..
and why did u put -3x^0 have 1 0 why not a 1?