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brynscalltoarms
May 14, 2012, 02:49 PM
(1+csc^2x) / (1+cscx) = (1+sinx) / sinx

I already attempted doing this and I basically got the right answer, except I got

sinx+1 / sinx instead of 1+sinx/sinx

ebaines
May 15, 2012, 06:30 AM
(1+csc^2x) / (1+cscx) = (1+sinx) / sinx

I already attempted doing this and I basically got the right answer, except I got

sinx+1 / sinx instead of 1+sinx/sinx

There seems to be a typo in your question - the expression:


\frac {(1+ csc^2x)} {1 + csc x}


equals neither \frac {1 + \sin x}{\sin x} nor \sin x + \frac 1 {\sin x}

Please check the expression the equation that you're working on..