Hi there
Could you please give me a step by step instruction of the following questions:

Make y the subject in
1/x^2-1/z^2=1/y^2

Thanks

I assume by 'make y the subject', you mean solve for y?

\frac{1}{x^{2}}-\frac{1}{z^{2}}=\frac{1}{y^{2}}

Multiply by x^{2}y^{2}z^{2}

\not{x^{2}}y^{2}z^{2}\cdot\frac{1}{\not{x^{2}}}-x^{2}y^{2}\not{z^{2}}\cdot\frac{1}{\not{z^{2}}}=x^ {2}\not{y^{2}}z^{2}\cdot\frac{1}{{\not{y^{2}}}

y^{2}z^{2}-x^{2}y^{2}=x^{2}z^{2}

Factor out y^{2}

y^{2}(z^{2}-x^{2})=x^{2}z^{2}

y^{2}=\frac{x^{2}z^{2}}{z^{2}-x^{2}}

y=\sqrt{\frac{x^{2}z^{2}}{z^{2}-x^{2}}}

y=\frac{xz}{\sqrt{z^{2}-x^{2}}}

Oh I'm terribly sorry... Thanks very much for your help I appreciate it.
I'll remember to rate your answers.
Thanks