Hi, I need to figure out how this expression looks as a single logarithm.

Remember that:


b \times \log (a)= \log (a^b),

and

\log (a) + \log (b) = \log (ab).

Apply these rules and you should get your answer.

Remember that:


b \times \log (a)= \log (a^b),

and

\log (a) + \log (b) = \log (ab).

Apply these rules and you should get your answer.

Thank you