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Find vertex of parabola given the equation x^2 2x - 4y 17
creee
Apr 16, 2012, 12:09 PM
X^2 + 2x - 4y + 17 = 0
ebaines
Apr 17, 2012, 05:46 AM
Rearrange the equation to put it into the stabdard formL:
(x-x_1)^2 = 4p(y-y_1)
Then the vertex is the point (x_1, y_1). And for future reference: p is the distance between the focus and the vertex.