In sexual reproduction, a line of genes on a DNA chain from a mother is paired with a matching chain from the father. In a baby that develops from the two gene contributors, the pair of traits on its DNA will ?

Well considering you just said that the two are the same it impossible. The female chromosomes would be XY or Xy or xY or xy depending on whether they are recessive or dominant. And the same goes for the father so specifications must be there

The baby would have 22 pairs of chromosome and an another pair that determines its sex. XX will make the baby a female and an XY make it a male. (there are no recessives of these sex alleles, just two different types: X or Y)
Then, the rest of the baby's traits are determined by the alleles each parent contributed for each trait. In complete dominance, one allele is dominant to the other (M=dominant m=recessive) and so the following combinations will express the dominant trait: Mm or MM. If both parents contributed a recessive allele, then the recessive trait will show, e.g. mm) In incomplete dominance, a mix of both alleles will show as a trait (e.g. a white flower and red flower making a pink flower) Finally in co-dominance, BOTH alleles will be expressed. Hope this is the info you were looking for.

As people have previously qouted on the xy and vice versa I will not mention this
However the rest of the baby's traits(hair skin coulour and so forth) are decided by the genes in them parents so if the father has blonde hair but the mothers is black the child will most likely be born with either black or blonde hair