a bubble of gas with a volume of 1.20 cm3 is released under water. As it rises to the surface, the temperature of the bubble increases from 27 C to 54 C and the pressure is cut to one-third of its initial value. What is the volume of the bubble at the surface.

The ideal gas law says PV=nrT, which can be rewritten as PV/T = nr. Since the right hand side of that equation is a constant (the number of moles of gas is not changing), the left-hand side must remain unchanged as the bubble rises.

Hence, you can say PV/T(underwater) = PV/T(surface).

P underwater is p.
P at the surface is p/3.

T underwater is 27C, or 300K.
T at the surface is 54C, or 327K.

V underwater is 1.2 cm^3.
V at the surface is??

Just plug in the values and solve for V at the surface.