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treypence05
Jan 25, 2012, 05:57 PM
I'm having trouble simplifying this. ^3 to the square root of negative 27

Aurora2000
Jan 26, 2012, 02:45 AM
Do you mean \sqrt{-27}^3 ?

You cannot solve it in the real numbers: \sqrt{-27}=3\sqrt{3}i , and \sqrt{-27}^3= -81\sqrt{3}i, where i:=\sqrt{-1} .

ebaines
Jan 26, 2012, 06:42 AM
I wonder if the OP means this:


\sqrt[3] {-27}


What you're looking for is the cube root of -27, or a number N that satisfies N \times N \times N = -27 . Here's a hint: if N is a negative number the result is also negative: for example of N = -2 then (-2) \times (-2) \times (-2) = -8. Perhaps now you can come up with a value for N that works?

Aurora2000
Jan 26, 2012, 07:06 AM
I think ebaines's guess makes more sense, but it is unusual to write "square root" in this case.