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wyattkendra
Dec 9, 2011, 10:09 AM
Assume that the average annual salary for a worker in the United States is $28,500 and that the annual salaries for Americans are normally distributed with a standard deviation equal to $6,250. Find the following:
(A) What percentage of Americans earn below $18,000?
(B) What percentage of Americans earn above $41,000?

Please show all of your work.

Unknown008
Dec 13, 2011, 04:48 AM
Define your variable first.

This is a normal distribution with mean 28,000 and standard deviation 6,250. Let X be the salary of a worker.

X ~ N(28000, 6250^2)

To get the percentage of Americans who earn below $18,000, take X < 18000.

Then use your z-table to find P(X < 18000), which would map onto:

P\(Z < \frac{18000-28500}{6250}\)

You use the same principle with the next part.