View Full Version : How should I calculate the determinant?
lemon14
Dec 2, 2011, 01:00 AM
\begin{vmatrix}
-2a & a+b & a+c \\
b+a & -2b & b+c \\
c+a & c+b & -2c
\end{vmatrix}
EDIT by Unknown008: Added the + signs.
lemon14
Dec 2, 2011, 01:05 AM
| -2a a+b a+c // b+a -2b b+c // c+a c+b -2c |
I have problems with displaying the "+" sign every time I post. Is there a specific rule for writing expressions containing "+" ?
Unknown008
Dec 2, 2011, 03:23 AM
You just need to type them in manually. That is after copy/pasting, you delete the + and retype them in and it should be fine I think.
Otherwise, wikipedia has an article about that and the determinant is:
(-2a)(-2b)(-2c) + (a+b)(b+c)(c+a) + (a+c)(b+a)(c+b) - (a+c)(-2b)(c+a) - (a+b)(b+a)(-2c) - (b+c)(c+b)(-2a)
It's just like taking the diagonals:
Longest diagonal towards down-right,
Other diagonals going down-right and getting on the other side.
Then subtracting the opposite diagonals.
lemon14
Dec 5, 2011, 07:41 AM
Sorry, it is my fault I didn't mention that I'm looking for another method (e.g. summing lines / columns or other operations) so that I can calculate it easier.
Regarding the + I typed each of them manually.
Unknown008
Dec 5, 2011, 08:51 AM
Barg, I don't know then... something to raise to the website developers, and it seems that they never took that seriously.
Otherwise, sorry, I don't know of any other method :(
lemon14
Dec 5, 2011, 01:18 PM
OK, thank you anyway.