f(x) 15x-2/x; f(a)=1 this is such a weird problem we don't under stand the steps requiered to find the answer

Given f(x) = 15x-2/x, the problem is asking you to find value(s) of 'a' such that f(a)=1. So you need to solve:

15a - 2/a = 1

You can multiply through by 'a' and rearrange to get a quadratic equation, then use the quadratic formula to find the two values for 'a' that satisfy this.