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tikki14
May 17, 2011, 12:06 PM
How to solve this sum of combinations?

C_n^2 + 2 C_n^3 + ... + (n-1) C_n^n

galactus
May 17, 2011, 03:38 PM
Look at the sum closely. N is a constant.

Say we have n=10.

All terms are 0 up to (10-1)C(10,10)=9

Regardless the value of n, this is true throughout.

So, the sum is n-1.

jcaron2
May 17, 2011, 09:06 PM
Took me a second before I saw it. You're right; there are exactly zero ways to choose n objects from a set of <n.

jcaron2
May 17, 2011, 09:08 PM
There was a "less than n" at the end of that previous comment, but apparently the interpreter thought my less than symbol was some sort of markup or directive. Either way, nice answer as usual, Galactus.