Find the locus of points in the plane satisfying each of the given conditions:
(i) |z-5| = 6 (ii) |z-2i| >=1 (iii) Re(z+2) = -1
(iv) Re{i(conjugate of z)} =3 (v) |z+i| = |z-i|
Also Sketch its diagram.
Please tell me as soon as possible...?

The locus of an equation of the forms:

|z - (x + iy)| = r

Is a circle with centre (x, y) and radius r.
The equal sign indicates that the locus is on the circumference. If that were to be replaced by a \geq sign, this will be on and outside the circumference of the circle.

Re(z + x+ iy) = p

That means that the real part of z + x gives p, meaning that the real part of z is equal to p - x.

|z - (x+ iy)| = |z - (a + ib)|

The locus of this is a line, along the perpendicular bisector of the line joining the points (x, y) and (a, b)