If a negative test charge with excess of 4.8 x 10^3 electrons feels a force of 7.75N to the left when placed to the left of a larger charged field. Calculate the electric field intensity and its direction.

1. use F = Eq

F is the force, E is the electric field strength and q is the charge of the test charge.

2. For the direction, you tell us what you think is right, and why you feel so :)