natardy
Apr 14, 2011, 09:16 AM
Pure mathematics/module 1/implicit differntiation
galactus
Apr 14, 2011, 10:25 AM
Implicitly differentiate
3x^{2}-y^{2}+xy=4
to get y'.
Set the result = to 8/3 and solve for y.
dvmohanrao
May 31, 2011, 06:59 PM
3x^2-y^2+xy=4
differentiate implicitly
6x - 2y y ' + x y ' + y = 0
y ' (2y - x) = 6x + y
y ' = (6x + y)/(2y - x)
since gradient is 8/3
=> (6x + y)/(2y - x) = 8/3
=> 18x + 3y = 16y - 8x
=> 13y = 26x
=> y = 2x