View Full Version : What make solution degerate in linear programming
enamel
Mar 17, 2011, 07:15 AM
smoothy
Mar 17, 2011, 08:08 AM
Homework rules...
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galactus
Mar 18, 2011, 05:50 PM
When a tie happens at least one basic variable will be zero in
the next iteration and the new solution is called 'degenerate'.
Say we wanted to maximize z=3x_{1}+9x_{2}
s.t. x_{1}+4x_{2}\leq 8
x_{1}+2x_{2}\leq 4
x_{1}, \;\ x_{2}\geq 0
I am not going to write up the tableau. Maybe you can do that if you wish to see what I am getting at.
In the starting iteration, x_{3} \;\ and \;\ x_{4} tie for the leaving variable. This is the reason the basic variable, x_{4}, is 0 in iteration 1, thus resulting in a degenerate basic solution. The optimum is reached after an additional iteration is carried out.
Graphically, three lines may pass through the optimum point. Because it is a 2-dimensional problem, the point is overdetermined and one of the constraints is redundant.
bkzd1989
Oct 16, 2013, 06:23 AM
How am I going to go about solving this with only a singular constraint and an unknown?
Refer to the following LP Formulation with unknown number S:
Max x1+x2
S.t
Sx1+x2 <= 1 x1,x2 => 0
How do I identify the unknown S to
(a) Having an optimal solution (b) Being infeasible (c) Being Unbound