western50
Mar 2, 2011, 10:31 PM
⋅ here means dot product
Here is a less coordinate-dependent "proof" of the same formula, (x(t)⋅y(t))=x(t)⋅y'(t)+x'(t)⋅y(t)... (1):
For small values of h, we have x(t + h) ≈ x(t) + hx'(t);
and similarly y(t + h) ≈ y(t) + hy'(t):
So for small h,
x(t + h)⋅y(t + h) ≈(x(t) + hx'(t))⋅(y(t) + hy'(t))
≈ x(t)⋅y(t) + h(x(t)⋅y'(t) + x'(t)⋅y(t));
and so
(x(t + h)⋅y(t + h)- x(t)⋅y(t))/h ≈ x(t)⋅y'(t) + x'(t)⋅y(t).
Taking the limit as h --> 0, the approximately equals sign "≈" changes into "=", and we get (1), which is the expression at the beginning.
So, I need to make this "proof" into a proof. In particular, your argument should use limits in a rigorous way, and not require making use of the ≈ symbol, and please give me help on how to do this problem because I really have no idea...
Here is a less coordinate-dependent "proof" of the same formula, (x(t)⋅y(t))=x(t)⋅y'(t)+x'(t)⋅y(t)... (1):
For small values of h, we have x(t + h) ≈ x(t) + hx'(t);
and similarly y(t + h) ≈ y(t) + hy'(t):
So for small h,
x(t + h)⋅y(t + h) ≈(x(t) + hx'(t))⋅(y(t) + hy'(t))
≈ x(t)⋅y(t) + h(x(t)⋅y'(t) + x'(t)⋅y(t));
and so
(x(t + h)⋅y(t + h)- x(t)⋅y(t))/h ≈ x(t)⋅y'(t) + x'(t)⋅y(t).
Taking the limit as h --> 0, the approximately equals sign "≈" changes into "=", and we get (1), which is the expression at the beginning.
So, I need to make this "proof" into a proof. In particular, your argument should use limits in a rigorous way, and not require making use of the ≈ symbol, and please give me help on how to do this problem because I really have no idea...