galactus
Feb 23, 2011, 06:04 AM
This is not a valid identity.
Perhaps you mean:
\frac{sin(x)+1}{cos(x)+cot(x)}=tan(x)
This is a valid identity. Convert the cot(x) to \frac{cos(x)}{sin(x)}.
\frac{sin(x)+1}{cos(x)+\frac{cos(x)}{sin(x)}}
Cross multiply the denominator, factor out a cos(x), cancel the resulting sin(x)+1 in the denominator with the one in the numerator, you will see a \frac{1}{\frac{cos(x)}{sin(x)}}. Which equals \frac{sin(x)}{cos(x)}=tan(x)