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western50
Feb 9, 2011, 05:54 PM
1. Consider the function f : R9 to R de fined as follows. For each vector a =
(a1; a2; : : : ; a9) in R9, let f(a) be the 3 by 3 determinant

a1 a2 a3
a4 a5 a6
a7 a8 a9

:
Is f a continuous function from R9 to R; why or why not?

please explain the concept to me!

jcaron2
Feb 9, 2011, 08:34 PM
You have a function f which maps points in 9-dimensional real space to 1-dimensional real space (i.e. a scalar). Even though it has more dimensions than you're used to working with, conceptually it's no different than a function which maps, say, two dimensional space. For example

f(x,y) = 3x - 2y + 6

maps R2 to R. For any coordinate pair (x,y), the function f(x,y) will have some real value, and it's pretty obvious that it's continuous. Changing x or y by some infinitesimal amount will result in an infinitesimal change in f(x,y).

Back to your question, since the function is simply the determinant of the matrix formed as indicated from the 9 coordinates, you can just write it out in long form:

f(a) = a1 * (a5*a9-a6*a8) - a2 * (... etc.

The determinant function is just some simple (albeit tedious) addition, subtraction, and multiplication. Like my simple 2-dimensional example, those are all continuous operations, so the function f(a) is continuous.

Does that make sense to you?

western50
Feb 10, 2011, 12:00 AM
So with what you said, because the determinant will give me some a real numbers, so that I can conclude from it that the function is continuous?

jcaron2
Feb 10, 2011, 06:23 AM
Yes, that's right. Not only are the answers real, but they change smoothly (i.e. continuously) as the values for a1 through a9 change.

western50
Feb 10, 2011, 11:25 AM
So is there any way making f(a) not continuous? Just a after thought

jcaron2
Feb 10, 2011, 03:02 PM
Sure. For example, if f(a) = 1/a1 + 1/a2 + 1/a3 +... + 1/a9, then it would be discontinuous at any point where one or more of the coordinates was 0. That's because the function blows up when the denominator goes to zero. Of course you could come up with an infinite variety of functions whose denominators go to zero at some point or points.

Likewise, if it included a discontinuous trig function like tan or csc, or any of countless others, it would map discontinuously.