I need help finding an equation & the answer to how to calculate 16 games to pick from (50/50 chance of being correct on any sports game) and the chance of getting it all correct.

I am thinking taking (1/2 x 1/2 x 16 times like that). Please tell me if I am correct?

I'm not sure what the problem is, but if you do what you suggested, you obtain 16/4 = 4.

A probability is always between 0 and 1, 0 being 100% sure it won't happen and 1 being 100% it will happen.

As you can see, yours is more than 100% sure to happen :eek:

Anyway, I'll try give another problem and you tell me if that's similar to your actual problem.

There are 16 questions with two answers each, one being correct and the other incorrect (of course). The probability of getting a correct answer is 1/2. What is the probability of getting all questions correct?

Like this? If so, then the probability will be:

P(all\ correct) = \(\frac12\)^{16} = \frac{1}{65536} \approx 0.000015258

That's nearly impossible to get everything correct by choosing randomly.