droby1242
Jan 15, 2007, 06:12 AM
How do I factor these problems
x^3-2x^2-4x-8
x^7y^2-4x^5yy^2-21x^3y^2
galactus
Jan 15, 2007, 01:03 PM
]How do I factor these problems
x^3-2x^2-4x-8
This one is not easily factorable. It has 2 complex roots.
Are you sure you don't mean x^{3}-2x^{2}-4x+8
Otherwise, as you have it, the factorization is(which I pumped out with Maple):
(x+\frac{14403}{17161}+\frac{23073}{19028}I)\left( x+\frac{14403}{17161}-\frac{23073}{19028}I\right)(x-\frac{63025}{17133})
x^7y^2-4x^5yy^2-21x^3y^2
Is this what you mean:
x^{7}y^{2}-4x^{5}y^{2}-21x^{3}y^{2}?
The y I have highlighted. I suppose it's errant?
If this is correct, then factor out x^{3} \;\ and \;\ y^{2}:
x^{3}y^{2}(x^{4}-4x^{2}-21)
Factor in the parentheses by letting u=x^{2}
(u^{2}-4u-21)=(u-7)(u+3)
Resub:
x^{3}y^{2}(x^{2}-7)(x^{2}+3)
Elisha Grey
Jan 17, 2007, 10:17 AM
If you mean x^3 - 2x^2 - 4x + 8, then this equals
x^2(x-2) - 4(x-2) = (x^2 - 4) (x-2) = (x+2)(x-2)^2