1) I need to find the maximum possible amount of PbI2, that Created in reaction between 0.3 mol Pb(NO3)2 to 0.2mol KI

Here is 4 answers Options:

A)0.1 mol

B)0.15mol

C)0.3 mol

D)0.5 mol

2) tell me if I correct , in this following list the most good Electrical resistance Compound in State of matter Liquid us AlF3 Because there is a Ionic bond YES?
A)CF4
B)AlF3
C)SF2
D)HF
Thanks :)

1)

Write the balanced chemical equation.
Find the mole ratio of Pb(NO3)2 to KI
From this, determine the limiting reagent.
Find the mole ratio of the limiting reagent to PbI2.
Use the number of moles of the limiting reagent and the mole ratio you just found to get the maximum amount of moles of PbI2 that you can get.

2) If AlF3 is in the molten state, then yes, it is the most conducting substance :)

hi. Thanks for answer but, I need help with to Write the balanced chemical equation.

I know that the basis equation is something like this: Pb(NO3)2+KI---->PbI2 but how I do the balanced ?
how do I know what Coefficient need to be in Which Material, if I was know any Coefficient is was make it Easier :)


for 2) yes is in molten state.

thanks.

Okay, count each type of atom on each side of the equation.

There are
Pb - ? Ions
NO3 - ? Molecular ions
K - ? Ions
I - ? Ions

Count those on the left, and those on the right, and you get:
Left:
Pb - 1 ion
NO3 - 2 molecular ions
K - 1 ions
I - 1 ions

Right:
Pb - 1 ions
NO3 - 0 molecular ions
K - 0 ions
I - 2 ions

You see what problem there is? You forgot K and NO3. Since Pb 'stuck' to I, K will go with NO3.

Then, you need 2 I on the left, hence put a 2 as coefficient of KI and let's see what happens.

Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + KNO_3

Count again. This time, you have one NO3 ion less on the right, and 1 K less on the right. So, put a 2 as coefficient in front of KNO3:

Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3

All is right now. Can you continue now? :)

Thanks for answer.

Well the mole ratio of Pb(NO3)2 to KI 1:2

But I am not got it how to continue . There is no any Formula to use? I not need to find m and Mm?

I know is hard to Explain to me ;)

Thank you

No, don't worry, if you don't know, we'll try to help you :)

Ok, from the mole ratio, you know that:
1 mol Pb(NO3)2 will react with exactly 2 moles of KI

Let's take Pb(NO3)2 itself, we have 0.3 mole of it.

How many moles of KI would this react with?
But then, how many moles of KI is there?

Hence, which one is there in excess and which one is limiting?

This is enough for now, but if you can , read my first and answer and try the last two steps :)

KI is the one is limiting.

so all the KI was react mean all the o.2 mol

and because the ratio of the mole between KI to Pb(NO3)2 is 2:1
so to know how many mole of Pb(NO3)2 is react with the KI I did 0.2/2=0.1 and this is the answer.

do I correct ?

thank you.

Yes, it is, now, how many moles of PbI2 do you obtain from 0.2 mol of KI, or from 0.1 mol of Pb(NO3)2?

(of course, you need to set up another mole ratio)

Also 0.1 Because the ratio between PbI2 and Pb(NO3)2 1:1 yes?

Yes! You got it right. Well done :)

:) thank you without your help I not sure if I was got it.