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View Full Version : Tan(x) sec(x)-1)/(tan(x)-sec(x) 1)=tan(x) sec(x)


samsonminda
Jan 18, 2011, 04:47 PM
Please help me verify this!

ebaines
Jan 18, 2011, 07:36 PM
Please retype the question, and this time please make sure that the parentheses match up. It seems like you mean this:


\frac {\tan (x) \sec (x) -1}{\tan (x)-\sec (x)+1} = \tan (x) \sec (x)


But this isn't correct. Please clarify.