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The number of bit strings contains four consecutive 0's and four consecutive 1's
k.rajesh3383
Dec 15, 2010, 03:52 AM
ebaines
Dec 15, 2010, 08:39 AM
Are you asking how many 8-bit bytes can be constructed consisting of 4 consecutive 0's and 4 consecutive 1's? The answer to that should be pretty obvious - you could have either 00001111 or 11110000. Or are you asking a different question?