PDA

View Full Version : PLEASE help.. STATISTICS (Normal distribution)


rej_ar
Dec 10, 2010, 01:31 AM
I need a step by step solution to this:
(The answers are already given; I just need the computations)
Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a tuna:
a. greater than 50 lbs Answer: 0.62%
b. less than 35 lbs Answer: 10.56%
c. between 32 and 36 lbs Answer: 13.59%
d. 36 and 48 lbs Answer: 81.85%

Thank you so much!!

rej_ar
Dec 10, 2010, 01:35 AM
Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a tuna:
a. greater than 50 lbs
b. less than 35 lbs
c. between 32 and 36 lbs
d. 36 and 48 lbs

rej_ar
Dec 10, 2010, 01:45 AM
Data indicates an average population weight of a fish of 40 lbs and a standard deviation of 4 lbs. Assume weight is normally distributed in the population. How probable was it to catch a fish:
a. greater than 50 lbs
b. less than 35 lbs
c. between 32 and 36 lbs
d. 36 and 48 lbs

Curlyben
Dec 10, 2010, 01:51 AM
Thank you for taking the time to copy your homework to AMHD.
Please refer to this announcement: https://www.askmehelpdesk.com/finance-accounting/announcement-font-color-ff0000-u-b-read-first-expectations-homework-help-board-b-u-font.html

Unknown008
Dec 10, 2010, 02:09 AM
You'll have to define your variable first.

Let X be the weight of a fish.

Then, X \sim N(\mu , \sigma^2)

You should know what are mu and sigma.

Then, the probability that the weight is greater than a certain value x,

P(X > x) = P(Z > \frac{x - \mu}{\sigma})

Then you look in your normal table and look for the probability associated with the z value.

Can you use this hint and solve your problem, then post the work that you did?