View Full Version : How the Derivative need to be
pop000
Dec 7, 2010, 02:10 AM
I got this Function 6/2radicallxl-1?
the x is into Absolute value and is into the radical.
I need to show the Derivative of this Function .
hope you Understand me :)
thanks
galactus
Dec 7, 2010, 06:44 AM
\frac{6}{2\sqrt{|x|}-1}
Consider both cases, the positive and negative.
Use the quotient rule.
\frac{6}{2\sqrt{x}-1}
\frac{6}{2\sqrt{-x}-1}
ebaines
Dec 7, 2010, 06:49 AM
It helps to use parentheses. Do you mean this:
\frac 6 {\sqrt{|x|}} -1
or this:
\frac 6 {\sqrt{|x|-1}}
or this:
\frac 6 {\sqrt{|x|}-1}
In any event, do as Galactus suggested - you'll have one answer for the domain x>=0, and another for x <0.
pop000
Dec 7, 2010, 08:33 AM
Thanks I Understand now :)