A small sphere of m = 0.17 kg is suspended by a light string from a vertical post mounted at the edge of a merry-go-round of radius R = 0.35 m. The equilibrium position of the sphere is shown in the figure, with `a' = 0.41 m and `b' = 0.88 m.
The axis of rotation is indicated by the dashed line. Calculate the angular velocity of the merry-go-round.
(in rad/s) ?
http://img406.imageshack.us/img406/3915/prob90set4fig1.gif

OK this is my last physics question for this week..

Set the ratio of the outward force on the ball (due to centripedal acceleration) to the ball's weight equal to the ratio of a to b.


\frac {m \omega^2 (R+a)} {mg} = \frac a b


Solve for \omega .

The funny thing is this is what I did haha but I for got the GGG.. damn my head..
Thanks ;)