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View Full Version : Find the exact value for sin(x y) if and . Angles x and why are in the 4thquadrant.


wallsa17
Dec 1, 2010, 06:06 AM
Remember: to show an identity is true, you have to prove it for all values of a variable. In order to prove that an expression is false, you only need to show one value of the variable that doesn't work. This is called a counterexample.

Sometimes you have trigonometric equations that are true for some values, but not for others.

When you provide a counterexample, you are looking for a value which results in an inequality instead of an equality.

Example:

Provide a counterexample that proves the equation is not a trigonometric identity.

Procedure:

1. Simplify each side as much as possible using trigonometric identities where possible.

2. Find a value that can be substituted into the equation that makes it an inequality.

Solution:
sin0cos0=cos0/sin0
sin^2 0cos0=cos0
sin^2 0=cos0/cos0
sin^2 0=1


Find a value for θ so sin2 θ ≠ 1.
If 0=30,sin0 = 1/2 and (1/2)^2=1/4 = 1

ebaines
Dec 1, 2010, 06:42 AM
The title of your post doesn't seem to match the problem you've worked out here. I assume your use of the characeter "0" iis meant to be \theta , and you are giving an example to show that:


\sin \theta \cos \theta \ne \cot \theta


If so, this looks good. However, the angle you chose for your example (30 degrees) is in the 1st quadrant, not the 4th.