I need to find the equation for a graph that has no y-intercept and starts at (1,1) the graph in creases at an increasing rate and the only part of the equation I have figured out is that it goes along the lines of 2^x(2 to the power of x), how do I make this equation?

2^x does have a y-intercept...

At x = 0, 2^0 = 1

And this line does not pass through (1, 1), but through (1, 2).

One easy curve is:

y = \frac{1}{x}

EDIT: This one decreases though... I'll be thinking of another one..

Maybe this will work, since y = x increases constantly and y = 1/x gradually, adding the two would give a constant increase.

y = \frac1x + x

or if the increase is not enough, you can boost it a little ;)

y = \frac1x + x^5

This question is answered here:

https://www.askmehelpdesk.com/math-sciences/square-coins-530619.html

Well, at least, the problem was more properly explained :rolleyes: