y=d(x-3)^2 p : find d
step by step answer please. I really want to try and fiqure this problem out.

Unless you have 2 points, or a graph with the relevant points indicated, you can't solve this.

oh wow I forgot to add the other number.. the function is y=d(x-3)^2+2

Ok, I'll assume that p = 2... but you still need a last point...

You can rearrange to get d by itself:


y = d(x-3)^2 +2 \\
y-2 = d(x-3)^2 +2 -2 = d(x-3)^2 \\
\frac {y-2} {(x-3)^2} = \frac {d(x-3)^2}{(x-3)^2} = d


So:


d = \frac {y-2} {(x-3)^2}


Per Unk's post, you can determine an actual value for d only if you have at least one (x,y) data point.