The sum of two numbers is 57. If the larger of the two numbers is 9 less than twice the smaller, find the two numbers.?

Let the two numbers be a and b, where a is the larger number.

Their sum is 57. So, we get:

a + b = 57

The second statement says that a is 9 less than b, when b is multiplied by two... that means that b is larger than a when it is doubled.

We get:
a + 9 = 2b

Meaning that only when you add 9 to a that those two results become the same.

Now, you have two equations and two unknowns. Solve for a and b using simultaneous equations.

a + b = 57
a + 9 = 2b