PDA

View Full Version : What is the standard form of a quadratic equation for 70-48/n-2 3=22?


shesler
Oct 5, 2010, 11:51 PM

ebaines
Oct 6, 2010, 05:51 AM
Is this what you're trying to ask?


70 - \frac {48} {(n-2)^3} = 22

?

Please use parentheses and brackets to make it clear what order of operatons you're trying to convey.

shesler
Oct 6, 2010, 05:45 PM
no sorry... 70-(48/n-2)+3=22

ebaines
Oct 7, 2010, 05:48 AM
I assume what you mean is this:


70 - \frac {48} {(n-2)} + 3 = 22


This is not a quadratic equation, as it does not involve a square of n. Are you sure you have the correct equation?

First thing is to group the numbers together:


73 - \frac {48} {(n-2)} = 22


and rearrange:

73 - 22 = \frac {48} {(n-2)} \\
51 = \frac {48} {(n-2)} \\
51(n-2) = 48 \\
51n - 102 = 48 \\
51n = 150 \\
n = \frac {150} {51} = \frac {50} {17}