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View Full Version : How to solve for q in the equation y=log(-log(1-q))


caddym31e
Oct 5, 2010, 07:41 PM

galactus
Oct 6, 2010, 04:28 AM
Just as e complements ln, 10 complements log.

Normally, logs are base 10 unless otherwise indicated.

y=log(-log(1-q))

-10^{y}=log(1-q)

10^{-10^{y}}=1-q

q=1-10^{-10^{y}}

q=1-(\frac{1}{10})^{10^{y}}

ebaines
Oct 6, 2010, 05:58 AM
Please do not double post the same question in two different forums. See: https://www.askmehelpdesk.com/math-sciences/logarithms-513991.html

It is interesting though that Galactus and Unknown008 got the answer in two different forms - though they are eqiuvalent.