galactus
Oct 6, 2010, 04:28 AM
Just as e complements ln, 10 complements log.
Normally, logs are base 10 unless otherwise indicated.
y=log(-log(1-q))
-10^{y}=log(1-q)
10^{-10^{y}}=1-q
q=1-10^{-10^{y}}
q=1-(\frac{1}{10})^{10^{y}}
ebaines
Oct 6, 2010, 05:58 AM
Please do not double post the same question in two different forums. See: https://www.askmehelpdesk.com/math-sciences/logarithms-513991.html
It is interesting though that Galactus and Unknown008 got the answer in two different forms - though they are eqiuvalent.