View Full Version : Average speed 2
Eloisea1
Oct 3, 2010, 06:12 AM
Ali walked 1km in 12 minuets. He stopped for 10 minuets and then walked a further 3km in 38 minuets. Calculate his average speed in km/h. I understand that average speed = total distance dive total time , so should I add the time ali stopped as well? Can anyone help please? Thanks.
Unknown008
Oct 3, 2010, 06:25 AM
Yes, you would add the time he stopped too. What counts, is the time he departed and the time he arrived.
Can you give what you get? :)
Eloisea1
Oct 3, 2010, 06:32 AM
So he walked 4km in 60mins so it is... 4 divide 60? Which is 0.06?
Unknown008
Oct 3, 2010, 06:40 AM
Hm... not quite.
What you got is the speed in km/min
Convert into hours as you were asked now.
In 1 minute, he covers 0.06666 km
In 60 minutes, he covers 0.06666 x 60 = 4 km/hr
Eloisea1
Oct 3, 2010, 06:56 AM
3.9996? I am confused :S
Unknown008
Oct 3, 2010, 07:03 AM
Right, but you didn't take all the numbers.
The actual distance he covers in 1 minute is \frac{4}{60}
Multiply that by 60, to get:
\frac{4}{60} \times 60 = 4
Eloisea1
Oct 3, 2010, 07:08 AM
So is it 4km/h?
Unknown008
Oct 3, 2010, 07:10 AM
Yes it is :)
Eloisea1
Oct 3, 2010, 07:24 AM
Thank you , and possibly 1 last question? I have posted it on average speed 3 , and have used what you taught me , darren ran a 200m race in 24 seconds what was his average speed for the race in m/s? Is it 8.3m/s and his av sp in km/h 20.88 km/h
Eloisea1
Oct 3, 2010, 07:52 AM
a. Darren ran a 200m race in 24 seconds. What was his average speed for the race in m/s. Is it 8.3? And also I have to find his average speed in km/h. can anyone help with both questions please?
Unknown008
Oct 3, 2010, 08:42 AM
i have posted it on average speed 3 , and have used what you taught me , darren ran a 200m race in 24 seconds what was his average speed for the race in m/s? Is it 8.3m/s and his av sp in km/h 20.88 km/h
1. Right
2. Not quite...
200 m = 0.2 km
24 s = \frac{24}{60}\ min = \frac{24}{3600}\ hours
So, speed = 0.2 \div \frac{24}{3600} = 0.2 \times \frac{3600}{24} = 30\ km/h
Or from you initial speed:
8.33\ m/s = 8\frac13\ m/s = 8\frac13\ m/s\ \times\ \frac{3600s}{1000m}\ =\ 30\ km/h