lemon14
Sep 25, 2010, 11:18 PM
after the combustion of 0.4 moles of organic substance results 32.4 g H2O, 4.756 L N2 at 290 K and 1 atm and a quantity of CO2 contained in 240 g solution of NaOH, concentration 40%. Which is the molecular formula of the organic substance?
a) C3H9N
b) C6H6N
c) C3H7N
what I did:
PV = nRT
1*4.756=n*0.082*290
n=0.2 moles of N2
18 g H2O... 1 mole of H
32.4 g H2O... x moles of H
x=1.8 moles of H but I don't think it is correct because the number of moles of N2, H and C should equal 0.4 and here the number of moles of H is bigger than 0.4
I also tried to go back, from the answers to the beginning of the problem, but I got only bad results. Please tell me where I am wrong and how to get the number of the moles of C. if I found these three numbers I could solve the rest of the problem.
ps: the answer in my book is a) C3H9N
thank you and sorry for my mistakes (I am not english)
a) C3H9N
b) C6H6N
c) C3H7N
what I did:
PV = nRT
1*4.756=n*0.082*290
n=0.2 moles of N2
18 g H2O... 1 mole of H
32.4 g H2O... x moles of H
x=1.8 moles of H but I don't think it is correct because the number of moles of N2, H and C should equal 0.4 and here the number of moles of H is bigger than 0.4
I also tried to go back, from the answers to the beginning of the problem, but I got only bad results. Please tell me where I am wrong and how to get the number of the moles of C. if I found these three numbers I could solve the rest of the problem.
ps: the answer in my book is a) C3H9N
thank you and sorry for my mistakes (I am not english)