How much it will take $10,000 to grow to $40,000 if the investment earn interst of 6% per year compounded daily

The formula for interest is:

A=P\left(1+\frac{r}{n}\right)^{nt}

Where P=amount invested
r=rate of interest as a decimal
n=# of compundings in a year.
t=# of years.

I believe 360 is used for n, instead of 365, in many cases.
You may have to verify that.

40000=10000\left(1+\frac{.06}{360}\right)^{360t}

solve for t.

Thanks a lot